Why does the metric have to be bilinear?
Posted by user4552, at physics.stackexchange.com,
Given a spacetime displacement $\textbf{x}$, we can define the interval $I(\textbf{x})$ as the square of the time measured by a…
Given a spacetime displacement $\textbf{x}$, we can define the interval $I(\textbf{x})$ as the square of the time measured by a…
Is there any freedom in choosing the weight of a tensor density? I have seen in some papers that they introduce a tensor…